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0000dca6f0
Can be reviewed with -W --ignore-all-space Fixes: * Calling ConsumeRandomLengthByteVector 4 times, when 2 is enough. * Slow execution speed: Finalize is expensive because it invokes division. Speed up the target by calling Finalize() at most twice per fuzz input.
58 lines
1.9 KiB
C++
58 lines
1.9 KiB
C++
// Copyright (c) 2020-2021 The Bitcoin Core developers
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// Distributed under the MIT software license, see the accompanying
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// file COPYING or http://www.opensource.org/licenses/mit-license.php.
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#include <crypto/muhash.h>
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#include <test/fuzz/FuzzedDataProvider.h>
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#include <test/fuzz/fuzz.h>
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#include <test/fuzz/util.h>
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#include <vector>
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FUZZ_TARGET(muhash)
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{
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FuzzedDataProvider fuzzed_data_provider{buffer.data(), buffer.size()};
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std::vector<uint8_t> data{ConsumeRandomLengthByteVector(fuzzed_data_provider)};
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std::vector<uint8_t> data2{ConsumeRandomLengthByteVector(fuzzed_data_provider)};
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MuHash3072 muhash;
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muhash.Insert(data);
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muhash.Insert(data2);
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const std::string initial_state_hash{"dd5ad2a105c2d29495f577245c357409002329b9f4d6182c0af3dc2f462555c8"};
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uint256 out;
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uint256 out2;
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CallOneOf(
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fuzzed_data_provider,
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[&] {
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// Test that MuHash result is consistent independent of order of operations
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muhash.Finalize(out);
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muhash = MuHash3072();
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muhash.Insert(data2);
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muhash.Insert(data);
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muhash.Finalize(out2);
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},
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[&] {
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// Test that multiplication with the initial state never changes the finalized result
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muhash.Finalize(out);
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MuHash3072 muhash3;
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muhash3 *= muhash;
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muhash3.Finalize(out2);
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},
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[&] {
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// Test that dividing a MuHash by itself brings it back to it's initial state
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muhash /= muhash;
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muhash.Finalize(out);
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out2 = uint256S(initial_state_hash);
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},
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[&] {
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// Test that removing all added elements brings the object back to it's initial state
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muhash.Remove(data);
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muhash.Remove(data2);
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muhash.Finalize(out);
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out2 = uint256S(initial_state_hash);
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});
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assert(out == out2);
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}
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